Question 46154
Factor:
{{{12x^3-3xy^2}}} First factor out 3x.
{{{3x(4x^2-y^2)}}} Notice that the term within the parentheses is the difference of two squares {{{(2x)^2 - (y)^2}}} and this will factor nicely because: {{{A^2-B^2 = (A+B)(A-B)}}}
{{{3x(2x+y)(2x-y)}}}