Question 443994
given:

{{{N(h)=1.6(h^(-1/2))}}}

{{{h=1.9}}}

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{{{N(1.9)=1.6((1.9)^(-1/2))}}}

{{{N(1.9)=1.6(1/sqrt(1.9))}}}

{{{N(1.9)=1.6(1/(1.378))}}}

{{{N(1.9)=1.6(0.73)}}}

{{{N(1.9)=1.168}}}