Question 443940
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Let me open by saying there is absolutely nothing wrong with the other tutor's answer.  However, allow me to give you an alternate way to look at how you present your answer.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-13\ \pm\ \sqrt{196\ -\ 4(13)(13)}}{26}\ =\ \frac{-13\ \pm\ \sqrt{-480}}{26}]


But then recognizing that 480 is equal to 16 times 30, we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-13\ +\ 4i\ \sqrt{30}}{26]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-13\ -\ 4i\ \sqrt{30}}{26]


which are the simplified exact answers as contrasted with the numerical approximations given.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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