Question 443834
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Hi
Note: vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
axis of symmetry for y=x^2-2 is  the y-axis
the vertex for y=x^2-2 is Pt(0,-2)
{{{drawing(300,300,   -6, 6, -6, 6, grid(1),
circle(0, -2,0.3),
graph( 300, 300, -6, 6, -6, 6,0,x^2-2))}}}