Question 443856
{{{3x^2-10x=-7}}}
{{{3x^2-10x+7=0}}}
You want to find two numbers that:
multiply to 7*3=21
and add to -10
therefore -3 and -7

{{{3x^2-3x-7x+7=0}}}
{{{3x(x-1)-7(x-1)=0}}}
{{{(3x-7)(x-1)=0}}}

So,
{{{3x-7=0}}}
{{{3x=7}}}
{{{x=7/3}}}
or
{{{x-1=0}}}
{{{x=1}}}

So therefore, x=7/3 or x=1 .