Question 46116
Standard Form: {{{y = ax^2 + bx + c}}}
Equation: {{{y = x^2 + 9}}}
a=1 : b=0 : c=9
vertex is found by: ((-b/2a),f(x))
((-0/2),f(x))
(0,f(x)) to find f(x), you plug in the x value into your equation: {{{y = 0^2 + 9 = 9}}}
(0,9)
{{{graph(600,600,-10,10,-2,18,x^2+9)}}}