Question 443756
Notice that each term has a common factor of 6.

Then you can factor it in this way {{{6(x^2+2x+1)}}}
From there factor the quadratic you are presented: {{{x^2+2x+1}}} Since 1*1 =1 and 1+1 =2, then we can factor this into {{{(x+1)(x+1) = (x+1)^2}}}
Then the total factorization is : 

{{{highlight(6(x+1)^2)}}}