Question 46107
log (x+3) + log (x) = 1
log (x^2+3x) = 1
x^2 + 3x = 10^1
x^2 + 3x - 10 = 0
(x + 5)(x - 2) = 0
x = -5 or x = 2
Remember that you can not take a logarithm of a negative number, so your answer is two.