Question 46085
Let the numbers be x and y
EQUATION 1:
xy=20
{{{y=20/x}}}
EQUATION 2:
{{{1/x+1/y=3/5}}}
SUbsitue for y:
{{{1/x+1/(20/x)=3/5}}}
{{{1/x+x/20=3/5}}}
{{{20+x^2=(3(20)(x))/5}}}
{{{20+x^2=60x/5}}}
{{{100+5x^2=60x}}}
{{{x^2-12x+20=0}}}
Factor
x=2 and y= 10
Hence, the two numbers are 2 and 10
Paul.