Question 443639
{{{2^(3x-1)=7^(x-q)}}}
{{{log2^(3x-1)=log7^(x-q)}}}
{{{(3x-1)log2=(x-q)log7}}}
{{{3xlog2-log2=xlog7-qlog7}}}
{{{3xlog2-xlog7=log2-qlog7}}}
{{{x(3log2-log7)=log2-qlog7}}}
{{{x=(log2-qlog7)/(3log2-log7)}}}

Is this okay as the final answer?
To leave it in log form.

You could also simplify:
{{{3log2-log7}}}
={{{log2^3-log7}}}
={{{log8-log7}}}
={{{log(8/7)}}}