<PRE><B>Question 443507</B>
A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 ton is 2000 pounds. (Round your answers to two decimal places.) 

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It appears that the sample mean is 15 tons.
No unit price sees to be available.
No standard deviation value is stated.
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The margin of error is zs/sqrt(n)
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For a 90% CI z = 1.645
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The CI will be 15-1.645s/sqrt(n) &lt; u &lt; 15+1.645s/sqrt(n)
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Cheers,
Stan H.</PRE>