Question 443491
{{{ -x^2-3x+4=0 }}}
Use quadratic equation
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{ a = -1 }}}
{{{ b = -3 }}}
{{{ c = 4 }}}
{{{x = (-(-3) +- sqrt( (-3)^2-4*(-1)*4 ))/(2*(-1)) }}}
{{{x = ( 3 +- sqrt( 9 + 16 ))/(-2)) }}}
{{{x = ( 3 +- sqrt( 25 ))/(-2)) }}}
{{{x = ( 3 - 5)/(-2) }}}
{{{ x = 1 }}}
and
{{{x = ( 3 + 5)/(-2) }}}
{{{x = -4 }}}