Question 443374
You start with f[g(-3)].
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Since it is on the inside, start with the g(-3), which is basically g(x). Therefore, if g(x)={{{sqrt(1-x)}}}, then g(-3)={{{sqrt(1-(-3))}}}
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f[{{{sqrt(1-(-3))}}}]
f[{{{sqrt(1+3)}}}]
f[{{{sqrt(4)}}}]
f(2)
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Since f(x)={{{x^2 + 4}}}, then f(2)={{{2^2 + 4}}}
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{{{2^2 + 4}}}
{{{4 + 4}}}
8
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Therefore, f[g(-3)]=8