Question 443408
x^2 = 4 - y
x = y + 2

then y = x-2 via the second equation... sub it back into the first.

x^2 = 4 - (x-2)
x^2 = 4 -x  +2
x^2 = 6 -x
x^2 +x -6 = 0
(x+3)(x-2) 
{{{highlight(x = -3)}}} {{{highlight(x =2)}}}

Plug each of these back in for x.

-3 = y +2
{{{highlight(-5 = y)}}}
2 = y +2
{{{highlight(0 = y)}}}

So we have two solutions, (-3,-5) and (2,0).

Let's check each of these.

x^2 = 4-y
x = y + 2

9  = 4 +5 = 9  Check.
-3 = -5 + 2 = -3 Check.

So (-3,-5) works.

=============
Try (2,0)

4  = 4 - 0 = 4 Check.
2  = 0 +2 = 2 Check.

Both solutions work.

Again the solutions are
{{{highlight(x = -3 )}}} {{{highlight(y = -5)}}}
{{{highlight(x = 2)}}} {{{highlight(y =0)}}}