Question 443363
{{{2^(x+1) + 5 =17}}}
Subtract 5.
{{{2^(x+1) = 12}}}
Take the log(base2) of both sides.
{{{log(2,2^(x+1)) = log(2,12)}}}
{{{x+1 = log(2,12)}}}
{{{ x = log(2,12) -1}}}
Use the change of base formula.
{{{log(b,a) = log(a)/log(b)}}} 
Stupid way to remember this: The base goes in the basement. :P
{{{ x = (log(12)/log(2)) - 1}}}
Put this in your calculator to get:
{{{highlight(x = 2.58)}}}