Question 443210


{{{x(2x+3)(5x-1)=0 }}}.here is a product of three factors; factor {{{x}}}, factor {{{2x+3}}}, and  factor {{{5x-1}}}.. if either one is equal to {{{0}}}, equation in whole will be equal to {{{0}}}

so, first solution is {{{x=0}}}

second solution is:

{{{2x+3=0}}}.....=>...{{{2x=-3}}}..=>...{{{x=-3/2}}}

third solution is:

{{{5x-1=0}}}.....=>...{{{5x=1}}}..=>...{{{x=1/5}}}