Question 442983
5^x = 7^(3x-1)
Take the ln of both sides.

Then xln(5) = (3x-1)ln(7)

Then 1 =(3x-1)/(x) ln(7)/ln(5)
1 = (3 - 1/x)ln(7)/ln(5)

ln(5)/ln(7) = 3 -1/x

ln(5)/ln(7) -3 = -1/x

Then {{{-1/(ln(5)/ln(7)-3) = x}}}
Or in decimal form: x = 0.46