Question 46050
Solve using the quadratic formula: 4x^2+12x=-3
4x^2+12x+3=0.....a=4....b=12...c=3
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-12 +- sqrt( 12^2-4*4*3 ))/(2*4) }}}
{{{x = (-12 +- sqrt( 96 ))/(8) }}}
{{{x = (-12 +- 4*sqrt(6))/(8) }}}
{{{x = (-3 +- sqrt( 6 ))/(2) }}}