Question 442639
3x^2 = -4x + 2 
put equation into the standard form
3x^2 + 4x - 2 = 0
The quadratic equation
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
In this equation: a=3, b=4, c=-2
{{{x = (-4 +- sqrt(4^2-4*3*-2 ))/(2*3) }}}
:
{{{x = (-4 +- sqrt(16-(-24) ))/6 }}}
Minus a minus is a plus
{{{x = (-4 +- sqrt(16+24 ))/6 }}}
:
{{{x = (-4 +- sqrt(40 ))/6 }}}
:
Find the square root. Two solutions
{{{x = (-4 + 6.3245)/6 }}}
x = {{{2.3245/6}}}
x = .387
and
{{{x = (-4 - 6.3245)/6 }}}
x = {{{-10.3245/6}}}
x = -1.721