Question 442898
The area of the floor is (5 ft)(8 ft) = 40 sq ft.


Because Sam does not want to spend more than $250, we set up an inequality,


*[tex \LARGE (40 ft^2)(\frac{$x}{ft^2}) \le $250]


*[tex \LARGE 40x \le 250]


*[tex \LARGE x \le \frac{250}{40} = 6.25]


Thus, the largest amount per square foot Sam can spend is $6.25 per sq ft.