Question 442766
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Hi
infinite geometric series {1 - 3/5, 9/25, - 27/125, ...}
   r = (-3/5)
{{{sum( a[n], n=1, infinity )}}} = {{{a[1]/(1-r)}}} when |r| < 1
{{{sum( a[n], n=1, infinity )}}} = {{{1/(1-(-3/5)) = 1/(8/5) = 5/8 }}} 




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