Question 442738
Use a sum or difference formula to find the exact value of the following. 
sin(190°)cos(10°)-cos(190°)sin(10°)= 
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sin(190) = sin(180+10) = sin(180)cos(10)+cos(180)sin(10) = 0-sin(10)
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cos(190) = cos(180+10) = cos(180)cos(10)-sin(180)sin(10) = -cos(10)-0
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Put those values in for sin(190) and cos(190) to get:
= (-sin(10)(cos(10)) -(-cos(10))(sin(10))
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= 0
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Cheers,
Stan H.