Question 442682
x^2-8x>0

Solve x^2-8x = 0

x(x-8) = 0

x =0 , x =8

{{{number_line(600,-10,15,0,8)}}}

Locate a point that is less than 0:

Let's choose -1. (-1)^2 + 8 = 9  POSITIVE. Remember this.

Choose a point between 0 and 8.

Let's choose 1. 1^1 - 8 = -7  NEGATIVE.

Choose a point greater than 8, choose 9.

9^2 - 8(9) = 9  POSITIVE. Remember this.

Find where y is positive:  When y<0  and when y>8.

Thus our answer is in interval notation ({{{-infinity}}},0) U (8,{{{infinity}}})

U means the union of.