Question 442674
Multiply and simplify 
8y^5/5x^3 times 25x^5/64y 
I came up with 5y^4x^2/8 is that correct
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[8y^5/5x^3] times [25x^5/64y]
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Cancel factors common to a numerator and a denominator
such as 8,5,y,x^3
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[y^4/1] times [5x^2/8]
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= (5/8)x^2y^4
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You are correct
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Cheers,
Stan H.
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