Question 442637
	Find the roots of the equation by quadratic formula						
							
a=	2	b=	-5	c=	-7		
							
b^2-4ac=25-56				
b^2-4ac=81{{{sqrt(81)}}}=9
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(5+9)/4		
x1=	3.5						
x2=(5-9)/4			
x2= 	-1