Question 442634
(x-2)(x+1)=8
x(x+1)-2(x+1)=8
x^2+x-2x-2=8
x^2-x-10=0

Find the roots of the equation by quadratic formula						
							
a=1,b=-1,c=-10		
							
b^2-4ac=1-40			
b^2-4ac=41{{{sqrt(41)}}}=6.4
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(1+6.4)/2		
x1=3.7						
x2=(1-6.4)/2			
x2= -2.7