Question 442662
I'm not sure I understand the question.
We can try completing the square:
{{{x^2 - 2x = 4}}}
{{{x^2 - 2x + 1  = 4 +1}}}
{{{(x-1)^2 = 5}}}
{{{sqrt((x-1)^2) = sqrt(5)
{{{abs(x-1) = sqrt(5)}}}
{{{ x-1  = sqrt(5)}}} and {{{-(x-1) = sqrt(5)}}}
{{{ x = sqrt(5) +1}}} and {{{x = -sqrt(5) + 1}}}

Maybe this is what they are asking for?

Hope this helped.