<PRE><B>Question 442577</B>
We have


*[tex \LARGE 7x + 2y = 5 \Rightarrow y = -\frac{7}{2}x + \frac{5}{2}]


Hence, the slope m is -7/2. Any perpendicular line will therefore have a slope of 2/7. We can express the desired line in point-slope form:


*[tex \LARGE y - (-7) = \frac{2}{7}(x - 7)]


*[tex \LARGE y + 7 = \frac{2}{7}(x-7)]</PRE>