<PRE><B>Question 442273</B>
Two houses on the same road are 10 miles apart. 
The angles formed between the road and the lines of sight from the houses to a
 cell phone tower are 51 degrees and 39 degrees.
 Find the distances between each house and the cell phone tower (round to nearest tenth)
:
Find the third angle: 180 - 51 - 39 = 90 degrees, so it is a right triangle
Therefore
sin(51) = {{{a/10}}}
.777*10 = a 
a = 7.8 mi, one house dist to tower
and
cos(51) = {{{b/10}}}
.629*10 = b
6.3 mi, the other house to the tower
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