Question 442571
Notice that {{{highlight(a^2)+2a+highlight(1)}}} are perfect squares.

{{{(a)^2 = a^2}}}
{{{(1)^2 = 1}}}

Then the factorization of {{{a^2+2a+1 = (a+1)^2}}}

Recall that {{{sqrt(x^2) = abs(x)}}}

Then {{{sqrt((a+1)^2) = abs(a+1)}}}

{{{abs(a+1)}}} is our answer.