Question 442491
Are we simplifying the expression?

If so, we have: {{{(x+1)(x-1)/(x+1)^2}}}

Recall, with like bases we can subtract exponents if we are dividing.

So, this becomes {{{(x+1)^(1-2) * (x-1) = (x+1)^-1 *(x-1)}}}

To simplify, we cannot have negative exponents, so we have to make everything in terms of positive exponents. Recall that a^-1 = 1/a. So (x+1)^-1 = 1/(x+1).

Thus our final answer is : {{{(x-1)/(x+1)}}}