Question 442472
Since the terminal side passes through (1, 2), the legs of the right triangle are 1 and 2 and its hypotenuse is {{{sqrt(1^2+2^2)=sqrt(5)}}}.If angel Q=x we get:

{{{sinx=2/sqrt(5)}}}; {{{cosx=1/sqrt(5)}}}; {{{tanx=2}}}; {{{cotx=1/2}}};

{{{secx=sqrt(5)}}} and {{{cscx=sqrt(5)/2}}}.