Question 442413
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi
w^4-12w^2-2=0   |Let w^2 = x
  x^2 - 12x - 2 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (12 +- sqrt( 152 ))/(2) }}}
{{{x = (12 +- sqrt( 4*38 ))/(2) }}}
{{{x =  6 +- sqrt(38) }}}     | w = ± {{{sqrt(x)}}} 
  w = ± {{{sqrt(6 +- sqrt(38))}}}
  w = ± 3.4878 and w = ± .1644i  Two real and two imaginary roots

{{{(x+sqrt(2))(x-7sqrt(2))= 0}}} = {{{x^2 - 6sqrt(2)x - 14 = 0}}}




ewatrrr@aol.com
private/pay tutoring Inquiries only, please.