Question 45920
{{{((6p -18)/9p)/((3p-9))/(p^2))}}} 
(I hope that I have represented the problem correctly) This is a case of invert the denominator and multiply
{{{((6p -18)/9p)*((p^2)/(3p-9))}}} 
{{{((2(3p-9)/9p))*((p^2)/((3p-9)}}} You can cancel a (3p-9)
{{{2*p^2/(9*p)}}} which yields {{{2p/9}}} Remember to cancel out a p
I hope this helps