Question 442304
Get a common denominator. Then all you have is a polynomial in the numerator that you have solve for. When you get your solution check to make sure it isn't an "extraneous solution." Let's say you get x=4, but in the denominator you had a (x-4), then x=4 would be an extraneous solution.

Here's an example:

{{{x/(4x+4) + 3x/4 = 10/(x+1)}}}

Find a common denominator: In this case it will be 4x+4.

Then x + 3x(x+1) = 10(4)
     ------------------
          4x+4    
Since we have a common denominator, we solve just the numerator.

Here is our concern now:

x + 3x(x+1) = 40

x + 3x^2 + 3x = 40

3x^2 + 4x = 40

3x^2 +4x - 40 = 0

Then you'd solve it: (why'd I pick such nasty numbers. :D)

Hope this helps!