Question 442315
{{{ x/3 + y/2 = 3}}}
{{{ x +y  = 10 - x + 2y}}}

It is within the rules to multiply by some number to make easier equations to work with. Notice that the GCD of 2 and 3 in the first equation is 6. Let's multiply by 6 so we get integer values.

Then we have {{{ 2x + 3y = 18 }}}
and   if we simplify the 2nd we have:   {{{2x -y =10}}}

It is apparent that we need to use elimination, specifically to eliminate the x variable.

So after subtracting the two equations we get:

{{{ 0x +4y = 8}}}

{{{y = 2}}}

Plug that back in to one of our original equations. Let's go with the 1st.

{{{x/3  + 2/2 =3}}}
{{{x/3 + 1 = 3}}}
{{{x/3 =2}}}
{{{x=6}}}

So our answer is (6,2) or {{{ x=6 }}} {{{y=2}}}