Question 442186
Solve the following equation for x in terms of q: 
2^(3x-1)=7(x-q)
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Take the log of both sides:
(3x-1)*log(2) = log[7x-7q]
Solve for "x":
3x-1 = [log(7x-7q)/log(2)]
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x = {[log(7x-7q)/log(2)]+1}/3
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x = {[log2(7x-7q)]+1}/3
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Cheers,
Stan H.