Question 442056
Hello, 
Let's represent the 4 integers as: x  (x+1) (x+2) (x+3) Now we can set up the following equation:
5(x+1+x+2)=7(x)-6
Rewritten as:
10x+15=7x-6
Subtract 7x and 15 from both sides to get:
3x=-21
Divide by 3:
x=-7
So now we know the integers are:
-7, -6,-5,-4
Make sense?
RJ
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