Question 441899
Plugging the coordinates of the points into {{{y=ax^2+bx+c}}}, we get the system:

{{{system(3=9a-3b+c, -1=25a+5b+c, 33=9a+3b+c)}}}. Subtracting first equation from 

the third we get:{{{30=6b}}} => {{{b=5}}}.Isolate c from the first and second 

equation:c=3-9a+3b and c=-1-25a-5b, from these two equalities we get:

3-9a+3b=-1-25a-5b simplifying this equality we get:4a+2b=-1, substituting b=5,

we have: 4a+2*5=-1 => a=-11/4. Substituting a and b we find c:

c=3+99/4+15 => c=171/4.

You can solve the system using Cramer's Rule.

Done.