Question 441846
An airline estimates that with probability 0.05 a passenger who purchased a ticket won’t take the designated flight. Suppose for a certain flight the airplane can carry 100 passengers and the airline sold 102 tickets.
--------------------------------------------

11. Find the probability that exactly 101 passengers show up to take the flight (4 digits after decimal point).
P(x = 101) = 0.95^101 = 0.0056
--------------------------------------
12. Find the probability that exactly 102 passengers show up to take the flight (4 digits after decimal point).
P(x = 102) = 0.95^102 = 0.0053
--------------------------------------

13. Find the probability that no more than 100 passengers show up to take the flight so the airline doesn’t have to compensate some people and ask them to leave the plane (4 digits after decimal point).
P(0<= x <= 100) = binomcdf(102,0.95,100) = 0.9660
========================================
Cheers,
Stan H.