Question 441748
First rectangle in inches
Let the width be x
The length is x + 11

Second rectangle in inches
The width is x - 5
The length is 2(x + 11)

The area of the second rectangle is 130 square inches bigger than the area of the first rectangle

Therefore
2(x + 11)(x - 5) - x(x + 11) = 130
(x + 11)(2x - 10 - x) = 130
(x + 11)(x - 10) = 130
x^2 + x - 110 = 130
x^2 + x - 240 = 0
(x - 15)(x + 16) = 0

Therefore x = 15 (it cannot be -16)

Check
15 by 26 is 390
10 by 52 is 520 which is 130 greater than 390

So for the first rectangle the width is 15 inches and the length is 26 inches
For the second rectangle the width is 10 inches and the length is 52 inches