Question 441645
There are 3 variations in signs ==> there could be 3 positive real roots, or just 1 positive real root.


Now when x is replaced by -x, the equation becomes {{{-4x^3 - 6x^2 - x - 3 = 0}}}, no variation in signs, hence there are no negative real roots.

Hence, either there 3 positive real roots, 

OR

1 positive real root and 2 distinct complex roots.