Question 441593
log2x+3log3(x-1)-log3(3-2x) 
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= log2(x) + log3(x-1)^3 - log3(3-2x)
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= log2(x) + log3[(x-1)^3/(3-2x)]
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Working with the base 2 term:

log2(x) can be written as log3(x)/log3(2) = (1/log3(2))log3(x)
= (log(3)/log(2))log3(x) = 1.5850*log3(x) = log3(x^1.5850)
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Getting back to the problem:
= log3(x^1.5850)+log3[(x-1)^3/(3-2x)]
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Final: log3[(x^1.5850*(x-1)^3)/(3-2x)]
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Cheers,
Stan H.