Question 441330
<pre>
Rule for multiplying two 3x3 matrices:

{{{(matrix(3,3,     
a,  b,  c,
d,  e,  f,
g,  h, i))(matrix(3,3, 
     j,  k,  l,
     m,  n,  p,
     q,  r,  s))=

(matrix(3,3,

aj+bm+cq, ak+bn+cr, al+bp+cs,
dj+em+fq, dk+en+fr, dl+ep+fs,
gj+hm+iq, gk+hn+ir, gl+hp+is))  




}}}

So, using the above rule:

 
{{{AB=(matrix(3,3,     
2,  3,  0,
-4,  2,  1,
3,  0, -2))(matrix(3,3, 
    -1,  2,  3,
     3,  0, -2,
     0,  4,  0))= (matrix(3,3,

   2(-1)+3*3+0*0,     2*2+3*0+0*4,    2*3+3(-2)+0*0,
  -4(-1)+2*3+1*0,    -4*2+2*0+1*4,   -4*3+2(-2)+1*0,
3(-1)+0*3+(-2)*0,  3*2+0*0+(-2)4,  3*3+0(-2)+(-2)*0))=

(matrix(3,3,
7,4,0,
10,-4,-16,
-3,-2,9))

}}}
                                  
Edwin</pre>