Question 441067
1. how long does it take 1700 to double if it invested at 5% interest , compound monthly?
2. what annual rate of interest is required to double an investment in 7 years?
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Compound interest formula:
A=P(1+i)^n,A= amount of investment after n periods, P=original investment, i=interest rate per period, n=no of periods.
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interest/period=.05/12
no of periods = n(months)
(1+i)=(1+.05/12)=1.00417
1) A/P=(1+i)^n
        2=1.00417^n
    log2=nlog1.00417
          n=log2/log1.00417
          n=166.56 months=166/12=13.88 years
ans: It will take around 13.9 years to double the 1700 investment at the annual interest rate of 5%
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2)  7 years=84 months=n
     2=(1+i)^84
  raise both sides by 1/84
  2^(1/84)=(1+i)^84)^(1/84)
  1.00829=1+i
  i=.00829 =monthly interest
 annual interest=12*.00829=.099=9.9%
Ans:
Annual interest required to double investment in 7 years is about 10%