Question 441006
the sum of the digits in a two-digit number is 7. The new number obtained when the digits are reversed is 27 less than the original number. Find the original number.
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original number: 10t+u
reversed number: 10u+t
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Equation:
t + u = 7
10t+u -(10u+t) = 27
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Rearrange:
t + u = 7
9t-9u = 27
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Rearrange:
t + u = 7
t - u = 3
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Add and solve for "t:
2t = 10
t = 5
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u = 2
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Original number: 
10t+u = 52
========================Cheers,
Stan H.