Question 440789
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Hi
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = -3x^2 -4
 1) parabola opens downward a = -3 < 0  Vertex Pt(0,-4) is a maximum pt
 2) Line of symetry is the y-axis
 3) relative to the the translation form the origin: down 4
{{{drawing(300,300, -10,10,-10,10, grid(1),
circle(0, -4,0.3),
graph( 300, 300, -10,10,-10,10, 0, -3(x)^2-4))}}}