Question 440801
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Hi
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x)=1/2x^2-6
 1) parabola opens upward a = 1/2 > 0  Vertex Pt(0,-6) is a minumum pt
 2) Line of symetry is the  y -axis
 3) relative to the the translation from the origin: down 6.
{{{drawing(300,300, -10,10,-10,10,   grid(1),
circle(0, -6,0.3),
graph( 300, 300, -10,10,-10,10, 0, .5x^2-6))}}}