<PRE><B>Question 440673</B>
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If the zeros of the function are -10 and 2, then the factors of the trinomial are *[tex \Large \left(x\ -\ (-10)\right)] and *[tex \Large (x\ -\ 2)].  Just multiply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ 10)(x\ -\ 2)\ =\ 0] 



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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