Question 45833
(4-3i)/(1+2i)

Multiply numerator and denominator by the 
conjugate of the denominator which is 1-2i, to get:

[(4-3i)(1-2i)]/[(1+2i)(1-2i)]
=[4-8i-3i-6]/[1+4]
=[-2-11i]/5
Cheers,
Stan H.